Understanding Parallel Resistors in Common-Emitter Amplifiers

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The discussion focuses on calculating the equivalent resistance of resistors in parallel, specifically in the context of a common-emitter amplifier's collector circuit. The formula used is rc = (RL^-1 + RC^-1)^-1, where RC is the collector resistor (12K ohms) and RL is the load resistor (50K ohms). Participants confirm that using this formula results in an equivalent resistance of approximately 9.68K ohms. The clarification helps one participant understand the calculation better. The thread illustrates the importance of grasping parallel resistor combinations in amplifier design.
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Quick question, i have a formula for finding rc (the ac resistance in the collector circuit) which is rc=RC(collector) is the parallel combination of RL I don't understand that for the example they have RC(collector resistor)= 12K ohms parallel to RL=50k ohms = 9.68K ohms.. someone explain the proper way to get 9.68k? Thanks
 
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Resistors in parallel add this way:

\left( 50k^{-1} + 12k^{-1} \right)^{-1} = 9.68k

- Warren
 
chroot said:
Resistors in parallel add this way:

\left( 50k^{-1} + 12k^{-1} \right)^{-1} = 9.68k

- Warren

yeah I figured it out, just had never seen it in those terms, thanks warren!
 

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