Commutation of Beam splitter operator with Displacement operator

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SUMMARY

The discussion centers on the commutation relationship between the beam splitter operator, represented as (a†)b + (b†)a, and the displacement operator, expressed as exp(α↠- α*â). Participants confirm that to determine if these operators commute, one must check the commutation of the beam splitter operator with the argument of the displacement operator's exponential. This analysis is crucial for understanding quantum optics and operator algebra.

PREREQUISITES
  • Understanding of quantum mechanics and operator algebra
  • Familiarity with creation (a†) and annihilation (a) operators
  • Knowledge of beam splitter and displacement operators
  • Basic principles of commutation relations in quantum physics
NEXT STEPS
  • Study the mathematical properties of beam splitter operators in quantum optics
  • Learn about the implications of operator commutation in quantum mechanics
  • Explore the role of displacement operators in quantum state manipulation
  • Investigate the applications of these operators in quantum information theory
USEFUL FOR

Quantum physicists, researchers in quantum optics, and students studying operator theory in quantum mechanics will benefit from this discussion.

deepalakshmi
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TL;DR
Does Beam splitter operator and Displacement operator of coherent state commute with each other?
I have a beam splitter operator (a†)b +(b†)a. Does it commute with exp(αâ†-α*â). Here a and ↠are creation and lowering operator
 
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Well, just check, whether the BS operator commutes with the argument of the operator exponential!
 

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