Commutator-like notation, index notation

Click For Summary
SUMMARY

The discussion centers on the use of commutator-like notation in field theory, specifically focusing on anti-symmetric expressions. The equations provided include $\Phi_{\mu\nu} = 2x_{[\mu}\partial_{\nu]}\phi$, $\Lambda^{\rho}_{\mu\nu} = 2x_{[\mu}\delta^{\rho}_{\nu]}L$, and $\partial_{[\mu}F_{\nu\rho]} = 0$. The notation indicates the need to account for permutations of indices, where the factorial of the number of terms in square brackets is used to normalize the expression. This method ensures the anti-symmetry of the terms involved, which is crucial in the context of electromagnetic tensors.

PREREQUISITES
  • Understanding of anti-symmetric tensors in field theory
  • Familiarity with permutation groups and their properties
  • Knowledge of electromagnetic tensor notation
  • Basic proficiency in LaTeX for mathematical expressions
NEXT STEPS
  • Study the properties of anti-symmetric tensors in depth
  • Learn about permutation groups and their applications in physics
  • Explore the derivation and implications of the electromagnetic tensor
  • Practice writing and manipulating expressions in LaTeX for clarity in mathematical communication
USEFUL FOR

This discussion is beneficial for physics students, particularly those studying field theory, as well as researchers and educators looking to deepen their understanding of tensor notation and its applications in theoretical physics.

ncs22
Messages
6
Reaction score
0

Homework Statement



There are some equations in the notes on field theory I am reading with notation I have never come across before. Someone told me it was a way of ensuring that the expression was anti-symmetric. I can't find it used the same anywhere else but no explanation is provided in the notes which makes me think maybe it is just an ordinary commutator but I am not sure.


Homework Equations



The equations are...

i. $\Phi_{\mu\nu} = 2x_{[\mu}\partial_{\nu]}\phi
ii. $\Lambda^{\rho}_{\mu\nu} = 2x_{[\mu}\delta^{\rho}_{\nu]}L
iii. $\partial_{[\mu}F_{\nu\rho]} = 0

F is the electromagnetic tensor if it helps.

The Attempt at a Solution



does the first mean...

\left(2x_\mu\partial_\nu\phi - 2x_\nu\partial_\mu\phi\right)

but then what do the others mean? For the second I was thinking of ignoring the superscript index - the rho - and doing the same as with the first but then what about the third one or am I not even close?

Thanks
 
Physics news on Phys.org
not really.
you have to divide by the factorial of the number of terms in square brackets and then you write out all the possible permutations of the terms in square brackets (where even permutations are positive and odd permutations are negative),

so 2x_{[\mu} \partial_{\nu]} \phi=2 \frac{1}{2!} \left(x_{\mu} \partial_{\nu} - x_{\nu} \partial_{\mu} \right) \phi = \left(x_{\mu} \partial_{\nu} - x_{\nu} \partial_{\mu} \right) \phi=

not this can get much more complicated. for example in your third case you'll have 6 permutations, 3 odd and 3 even. recall a permutation is odd if it can be written as an odd number of transpositions and even if it can be written as an even number of transpositions.
 
awesome! thanks
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
8K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 9 ·
Replies
9
Views
816
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
1
Views
4K
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K