Comparing 2 formula derivations

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The discussion focuses on defining the moment of inertia and deriving the expression for angular momentum in a rigid body. It explains that the moment of inertia considers particles at varying distances from the axis of rotation, specifically using perpendicular distances. In contrast, the angular momentum derivation treats the position as a 3-D vector, which introduces additional complexity due to components in multiple dimensions. The distinction arises because moment of inertia is a scalar quantity, while angular momentum is a vector quantity. This difference in treatment is clarified by a physics teacher's explanation.
Vykan12
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Here is how my book goes about defining the moment of inertia.
To begin, we think of a body as being made up of a large number of particles, with masses m_1, m_2, ... at distances r_1, r_2, from the axis of rotation. [...] The particles don't necessarily all lie in the same plane, so we specify that r_i is the perpendicular distance from the axis to the ith particle.

Now here's how my book goes about deriving an expression for the angular momentum of a rigid body.
We can use eq (10.25) to find the total angular momentum of a rigid body rating about the z axis with angular speed w. First consider a thing slice of the body lying in the xy plane.

From this the book derives that L = Iw
We can do the same calculation for other slices of the body, all parallel to the xy-plane. For points that do not lie in the xy-plane, a complication arises because the r vectors have components in the z direction as well as the x and y directions.

My question is in regards to the bolded part. How come in one derivation we assume r_i is a measure of the perpendicular distance from the axis of rotation, and in the other we made no such distinction, but rather considered r_i a 3-D vector?
 
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My physics teacher answered this for me.

The only reasons the derivations are different regarding r_i is because inertia isn't a vector whereas angular momentum is.
 
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