Imagine an ordinary car wheel with rubber tire, installed in a car axle. So the weight of the car (some of the weight of course, because there are 4 wheels) is pressing on it. Let's denote this pressure of the air in the tire as [itex]P_{c}[/itex].(adsbygoogle = window.adsbygoogle || []).push({});

Now the same wheel (with its rim and tire) remove from the car axle, so it is now freely lying on the floor. Hence no car weight is pressing on it. Let's denote the pressure of the air in the tire as [itex]P_{f}[/itex].

Question: Is [itex]P_{c}[/itex] different than [itex]P_{f}[/itex] ? How to show it by using ideal gas law equation? You may assume the weight of the rim as negligible if needed.

My personal guess: [itex]P_{c}[/itex] is more than [itex]P_{f}[/itex] because with the weight of the car pressing on the tire, volume of tire (hence volume of gas) reduces, thus pressure increases. In other words, if a tire pressure is 30psi while installed on car, once take it out from the car axle, its pressure will drop.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Comparing pressure of air in a tire installed in a car & a free tire

**Physics Forums | Science Articles, Homework Help, Discussion**