Comparing Surface Areas of Two Water Balloons Using a Formula

AI Thread Summary
The discussion focuses on comparing the surface areas of two water balloons using the formula ((4pi)^(1/3))((3v)^(2/3)). One balloon contains twice the volume of the other, leading to a calculation where the surface area of the larger balloon is found to be approximately 1.59 times that of the smaller balloon. The solution involves substituting the volumes into the formula and simplifying the expressions. After applying the formula, the user confirms the calculation aligns with the book's answer. This method effectively demonstrates the relationship between volume and surface area in spherical shapes.
darshanpatel
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Homework Statement



The question wants me to use this formula: ((4pi)^(1/3))((3v)^(2/3))

You have filled two round water balloons with water. One balloon contains twice as much water as the other balloon.

Compare the surface areas of the two water balloons using the given formula.

Homework Equations



None

The Attempt at a Solution



I don't know where to start
And I Don't Know where they got the answer from.

The book gave me a final answer as: The balloon with twice as much water will have about 1.59 times the surface area of the balloon with less water.
 
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Say the volume of the other balloon is x. The volume of the first balloon is twice the volume of the other balloon, so that's 2x. Plug in x into the formula above and simplify. Then do the same for 2x. Compare the two expressions.
 
ok, will try and let you know
 
Yes, it worked, I got about 1.59, thank you
 

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