Comparison Test: Am I using a good comparison function?

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SUMMARY

The discussion centers on evaluating the convergence of the integral \(\int^9_1 \frac{-4}{\sqrt[3]{x-9}} \, dx\). A participant suggests using the comparison function \(\int^9_1 \frac{-4}{x-9} \, dx\) to demonstrate that the original integral does not diverge. However, it is concluded that a comparison test is unnecessary, as the integral can be directly evaluated as an improper integral by taking the limit as \(M\) approaches 9.

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Homework Statement


Does the following interval diverge?
\int^9_1 \frac{-4}{\sqrt[3]{x-9}}


Homework Equations





The Attempt at a Solution


Well.. I've used the following function that I think is always less than the above function to prove that the function above DOES NOT diverge (by showing that the function below converges). I'm just wondering if this is an appropriate way of telling that the function above does not diverge...

\int^9_1 \frac{-4}{x-9}
 
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You don't need a comparison test. You can integrate that function. Just treat it as an improper integral. Integrate from 1 to M and let M approach 9.
 

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