Complex Analysis: Analytic Function F(z)?

asi123
Messages
254
Reaction score
0

Homework Statement



Hey guys.
I have this question, I took it from a test.
I need to check if there is an analytic function F(z) in this area (in the pic) that has this derivative (in the pic).

http://img256.imageshack.us/img256/7826/25453238.jpg

Well, the derivative is analytic in this area, right?
If the derivative is analytic, shouldn't F(z) be analytic and even more important, can it be that easy ?
I'm not sure about the answer, I could really use some help.

Thanks a lot.


Homework Equations





The Attempt at a Solution

 
Last edited by a moderator:
Physics news on Phys.org
If F'(z) has an antiderivative in the set described, then its integral around any closed curve in that set will be zero. Are you sure that happens? Consider what form an antiderivative of F'(z) would have, and what functions would be involved.
 
Wretchosoft said:
If F'(z) has an antiderivative in the set described, then its integral around any closed curve in that set will be zero. Are you sure that happens? Consider what form an antiderivative of F'(z) would have, and what functions would be involved.

The antiderivative of F'(z) will probably involve Ln, and Ln is not analytic in this set.
Is that what you mean?

Thanks a lot.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top