Complex Analysis: Analytic Function F(z)?

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SUMMARY

The discussion centers on determining the existence of an analytic function F(z) given its derivative F'(z) in a specified area. It is established that if F'(z) is analytic, then F(z) should also be analytic; however, complications arise if F'(z) has an antiderivative that includes the natural logarithm function, which is not analytic in the given set. The conclusion emphasizes the necessity of examining the nature of the antiderivative to ascertain the analyticity of F(z).

PREREQUISITES
  • Understanding of analytic functions in complex analysis
  • Knowledge of derivatives and antiderivatives in the context of complex functions
  • Familiarity with the properties of the natural logarithm function
  • Basic concepts of contour integration and closed curves in complex analysis
NEXT STEPS
  • Study the properties of analytic functions in complex analysis
  • Learn about the implications of the Cauchy-Goursat theorem on contour integrals
  • Investigate the conditions under which a function has an antiderivative in a given domain
  • Explore the role of branch cuts in the analyticity of logarithmic functions
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Students and professionals in mathematics, particularly those studying complex analysis, as well as educators looking for insights into the properties of analytic functions and their derivatives.

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Homework Statement



Hey guys.
I have this question, I took it from a test.
I need to check if there is an analytic function F(z) in this area (in the pic) that has this derivative (in the pic).

http://img256.imageshack.us/img256/7826/25453238.jpg

Well, the derivative is analytic in this area, right?
If the derivative is analytic, shouldn't F(z) be analytic and even more important, can it be that easy ?
I'm not sure about the answer, I could really use some help.

Thanks a lot.


Homework Equations





The Attempt at a Solution

 
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If F'(z) has an antiderivative in the set described, then its integral around any closed curve in that set will be zero. Are you sure that happens? Consider what form an antiderivative of F'(z) would have, and what functions would be involved.
 
Wretchosoft said:
If F'(z) has an antiderivative in the set described, then its integral around any closed curve in that set will be zero. Are you sure that happens? Consider what form an antiderivative of F'(z) would have, and what functions would be involved.

The antiderivative of F'(z) will probably involve Ln, and Ln is not analytic in this set.
Is that what you mean?

Thanks a lot.
 

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