Entire Functions Bounded by Exponential Growth

Sistine
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Homework Statement


Find all entire functions f such that

|f(z)|\leq e^{\textrm{Re}(z)}\quad\forall z\in\mathbb{C}


Homework Equations


\textrm{Re}(u+iv)=u


The Attempt at a Solution



I tried using Nachbin's theorem for functions of exponential type. I also tried using the Cauchy integral formula to see if I could gain more information about f but I could not solve the problem.
 
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I think you are looking at it in an overly complicated way. Can you think of a way to use |e^z|=e^(Re(z))?
 
I tried applying schwarz lemma to |f(z)|\leq |e^z| i.e.

\left|\frac{f(z)}{e^z}\right|\leq 1

But this did not give me much information about f. What other Theorems from Complex Analysis could I use to gain information about f?
 
Sistine said:
I tried applying schwarz lemma to |f(z)|\leq |e^z| i.e.

\left|\frac{f(z)}{e^z}\right|\leq 1

But this did not give me much information about f. What other Theorems from Complex Analysis could I use to gain information about f?

Liouville's theorem!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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