Complex Analysis: Properties of Line Integrals

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SUMMARY

The discussion centers on proving the equality \(\int_{-\gamma} f(z)|dz| = \int_{\gamma} f(z)|dz|\), where \(\gamma\) is a piecewise smooth path and \(f\) is continuous on \(|\gamma|\). The proof involves a substitution of \(u = -z\), which effectively reverses the direction of the path. This transformation is crucial for demonstrating the equivalence of the integrals over the original and reversed paths.

PREREQUISITES
  • Understanding of complex analysis concepts, particularly line integrals.
  • Familiarity with piecewise smooth paths in the context of integration.
  • Knowledge of substitution methods in integral calculus.
  • Basic proficiency in handling continuous functions in complex domains.
NEXT STEPS
  • Study the properties of line integrals in complex analysis.
  • Learn about the implications of path direction on integral values.
  • Explore substitution techniques in complex integrals.
  • Investigate the continuity of functions over piecewise smooth paths.
USEFUL FOR

Students and professionals in mathematics, particularly those focusing on complex analysis, as well as educators looking to enhance their understanding of line integrals and their properties.

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Homework Statement



Demonstrate that [tex]\int_{-\gamma} f(z)|dz|=\int_{\gamma} f(z)|dz|[/tex] where [tex]\gamma[/tex] is a piecewise smooth path and f is a function that is continuous on [tex]|\gamma|[/tex].


Homework Equations





The Attempt at a Solution



This proof seems like it should be very simple, but I am not sure it is really saying that it's just turning a path around to go in the opposite direction. Could someone please help me out? Thanks.
 
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Consider the substitution u= -z.
 

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