- #1
fred2028
- 19
- 0
I know that a 2nd order homo ordinary differential equation's solution is in the form of
[tex]\[f(x) = {C_1}{e^{{a}t}} + {C_2}t{e^{{a}t}}\][/tex]
for repeated real roots of the characteristic equation, and that the solution for a single complex root (and its conjugate) involves a cosine. I'm curious as to what the solution to a complex repeated root would look like?
[tex]\[f(x) = {C_1}{e^{{a}t}} + {C_2}t{e^{{a}t}}\][/tex]
for repeated real roots of the characteristic equation, and that the solution for a single complex root (and its conjugate) involves a cosine. I'm curious as to what the solution to a complex repeated root would look like?