Component functions and coordinates of linear transformation

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SUMMARY

The discussion centers on the linear transformation defined by the function f(t) = (1 - t) A + t A', where A(a, b, c) and A'(a′, b′, c′) are points in R3. The user inquires about expressing the component functions of f in terms of the coordinates of A and A' and the parameter t. It is clarified that the components x, y, and z can be derived directly from the expressions for (1 - t)A and tA', rather than involving partial derivatives. The correct expressions for x, y, and z are (1 - t)a + ta', (1 - t)b + tb', and (1 - t)c + tc', respectively.

PREREQUISITES
  • Understanding of linear transformations in R3
  • Familiarity with vector notation and operations
  • Knowledge of parameterization of lines in vector spaces
  • Basic calculus concepts, specifically derivatives
NEXT STEPS
  • Study the derivation of vector functions in R3
  • Learn about linear combinations and their geometric interpretations
  • Explore the concept of parametric equations in three-dimensional space
  • Investigate the application of partial derivatives in multivariable calculus
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Students and professionals in mathematics, physics, and engineering who are working with linear transformations and vector calculus will benefit from this discussion.

raghad
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Let A(a, b, c) and A'(a′,b′,c′) be two distinct points in R3. Let f from [0 , 1] to R3 be defined by f(t) = (1 -t) A + t A'. Instead of calling the component functions of f ,(f1, f2, f3) let us simply write f = (x, y, z). Express x; y; z in terms of the coordinates of A and A, and t. I thought that a is the partial derivative of f1 with respect to x, b is the partial derivative of f2 with respect to y, and c is the partial derivative of f3 with respect to z. I am right? Any hint how to find the relation and to find the derivative of f?
 
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raghad said:
Let A(a, b, c) and A'(a′,b′,c′) be two distinct points in R3. Let f from [0 , 1] to R3 be defined by f(t) = (1 -t) A + t A'. Instead of calling the component functions of f ,(f1, f2, f3) let us simply write f = (x, y, z). Express x; y; z in terms of the coordinates of A and A, and t. I thought that a is the partial derivative of f1 with respect to x, b is the partial derivative of f2 with respect to y, and c is the partial derivative of f3 with respect to z. I am right? Any hint how to find the relation and to find the derivative of f?

I don't see why you think partial derivatives come into this. ##(1-t)A=(1-t)(a,b,c)=((1-t)a,(1-t)b,(1-t)c)##. Now do something similar for ##tA'## and just add them.
 

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