Compound Hydrolization with Water and Acid

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Superkevs22
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Hi guys, I have a chemistry question which has been disturbing me. :cry: Please help me, it goes like this.

A liquid, C6H12O2, was hydrolyzed with water and acid to give an acid A and an alcohol B. Oxidation of B with chromic acid produced A. The formula of the original compound is?

I will attach the image for the choices since I have no idea how to turn the following compounds in a linear equation :frown: Choice A which is highlighted in yellow was the answer provided.

http://imgur.com/iBtgRFI

Could you please explain why the Choice A is the answer because I'm quite confused thinking that Choices A, B, and C are all possible answers because there is a carbonyl group. If you may also please include why choice D is not the answer? Help will be appreciated. :cry:
 
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When alcohol B is oxidized it produces the acid A. What does it tell you about number of carbon atoms in both compounds?
 
I see! I get it now! That must mean that if alcohol B oxidation yields exactly acid A they should have the same amount of carbons coming from the original compound which has equal amounts of carbon before and after the carbonyl group, is that correct sir?