Compound Hydrolization with Water and Acid

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The discussion revolves around the hydrolysis of the compound C6H12O2, which yields an acid A and an alcohol B. The oxidation of alcohol B with chromic acid produces acid A, indicating that both compounds share the same number of carbon atoms. The user is confused about why Choice A is the correct answer among several options, including the reasoning behind the exclusion of Choice D. The conversation highlights the importance of understanding the relationship between the structures of the compounds involved in the reaction. Ultimately, the user gains clarity on the carbon count in the original compound and its derivatives.
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Hi guys, I have a chemistry question which has been disturbing me. :cry: Please help me, it goes like this.

A liquid, C6H12O2, was hydrolyzed with water and acid to give an acid A and an alcohol B. Oxidation of B with chromic acid produced A. The formula of the original compound is?

I will attach the image for the choices since I have no idea how to turn the following compounds in a linear equation :frown: Choice A which is highlighted in yellow was the answer provided.

http://imgur.com/iBtgRFI

Could you please explain why the Choice A is the answer because I'm quite confused thinking that Choices A, B, and C are all possible answers because there is a carbonyl group. If you may also please include why choice D is not the answer? Help will be appreciated. :cry:
 
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When alcohol B is oxidized it produces the acid A. What does it tell you about number of carbon atoms in both compounds?
 
I see! I get it now! That must mean that if alcohol B oxidation yields exactly acid A they should have the same amount of carbons coming from the original compound which has equal amounts of carbon before and after the carbonyl group, is that correct sir?
 
Don't sir me, or I will ban you.

Other than that, you are right.
 
Thanks Admin!
 
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