Can 25 PSI Methane Flow Through a 3/8 Pipe Meet a 392,000 BTU/hr Demand?

AI Thread Summary
The discussion focuses on determining whether a methane flow at 25 psi through a 3/8" pipe can meet a demand of 392,000 BTU/hr. Key considerations include calculating the mass flow rate of methane based on its calorific value and the required heat flow rate. Participants suggest using empirical equations from resources like Crane TP410 for piping calculations and emphasize the importance of knowing methane's density at the specified pressure and temperature. The conversation highlights the need for precise calculations to ascertain if the existing setup can satisfy the BTU demand. Accurate assessments of gas flow and pipe diameter are crucial for meeting the heating requirements.
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What are the governing equations for compressible fluid flow?
Specifically; methane gas inlet pressure of 25 psi through a 3/8" dia. pipe and I need to relate this to a methane flow of 392,000 BTU/ hr @ 55-60psi 59 F and RH 60% (i.e. ISO 2314) through an as yet undetermined diameter pipe, assume methane has 1,000 BTU/cu. ft. @ ISO 2314. I'm not sure if there's sufficient gas @ 25 psi through the 3/8" tube to meet the demand. Thanks for your insights!
 
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First get the mass flowrate of methane. If you know the calorific value in btu/lb (better NCV or LHV), then total heat flowrate/LHV gives you mass flowrate of methane in lb/hr. That is the mass flowrate you require at any pressure. For piping calculation, if you can get an equation that directly deals with mass flowrates, nothing is better. Otherwise, get the density of methane at 25psi (a?g?) and the corresponding temperature and calculate the volumetric flowrate. Use the emperical equations given in Crane TP410 or in your local codes, if any.
 

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