Compressing a bottle with water - initial velocity of water

AI Thread Summary
To find the initial velocity of water ejected from a squeezed bottle with a hole, one must determine the internal pressure of the fluid, considering the material properties of the bottle. Pascal's law alone is insufficient; the area of the hole and the stress applied to the bottle are crucial factors. An experimental approach is suggested, where squeezing the bottle while holding it horizontally can provide data on the horizontal distance traveled by the water before hitting the ground. This distance, combined with the time of fall, can yield a rough approximation of the initial velocity. Understanding these dynamics is essential for accurate calculations.
ChessEnthusiast
Messages
115
Reaction score
3
Imagine that we have a closed plastic bottle filled with water and then we punch a hole with area A in its cap. How can I find the initial velocity the water will he "fired" with if we squeeze the bottle applying stress S?
Assume that we know all about the bottle (moduli, change in volume etc.
I guess that the Pascal's law is not enough here and it's got a lot to do with the material the bottle is made of.
 
Physics news on Phys.org
The exterior pressure will be 1 atmosphere. So you need to know the interior pressure and the diameter of the hole you cut.
Here is a link to a calculator:
http://www.tlv.com/global/TI/calculator/water-flow-rate-through-orifice.html

You do need to determine the pressure of the fluid in the bottle.

Perhaps the easiest way of determining this is to perform the experiment. When you squeeze the bottle, hold it horizontally 1 meter above the floor. The fluid will eject horizontally and the fall to the floor. The height above the floor will give you about a 0.31 second delay. The distance that the water moves horizontally before hitting the floor will tell you how far it traveled in that amount of time. It would be a rough approximation.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top