Compton Wavelength, h and h bar

  • Thread starter Thread starter Badger01
  • Start date Start date
  • Tags Tags
    Wavelength
AI Thread Summary
The discussion clarifies two representations of the Compton wavelength: λ = h/(mc) and λ = ħ/(mc), where ħ is the reduced Planck's constant. The first equation represents the proper Compton wavelength, while the second is referred to as the reduced Compton wavelength. The reduced form is often preferred in calculations due to the frequent appearance of factors of 2π in physics. Understanding when to use each form depends on the context of the problem being solved. Both representations are valid, but the reduced form is commonly utilized for its convenience in various applications.
Badger01
Messages
7
Reaction score
0
I have found 2 different representations of Compton wavelength:

\lambda=
\frac{h}{mc}
and
\frac{\bar{h}}{mc}
which of these is correct, and if both are right, how do you know when to use one or the other?
(note: the second equation contains a h bar as in " h bar = h/2pi ")
 
Last edited:
Physics news on Phys.org
The proper Compton wavelength is the first equation. The second equation is the reduced Compton wavelength, and it's used more frequently because factors of 2pi pop up all over the place.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top