Compute Gradient in GR: Step-by-Step Guide

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Discussion Overview

The discussion revolves around the computation of the extrinsic curvature in the context of general relativity, specifically for a metric describing the interior and exterior of a bubble. Participants are exploring the application of the formula for extrinsic curvature and the correct approach to substituting values into the equation.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses confusion about executing the calculation of extrinsic curvature using the provided metric and formula, seeking initial help with substitutions.
  • Another participant clarifies that ##N_{\mu;\nu}## refers to the covariant derivative of ##N_\mu##.
  • A later reply emphasizes the use of the Einstein summation convention for summing indices, explaining that each component of ##K_{ab}## involves summing over multiple indices.
  • There is mention of the specific components of the Christoffel symbols relevant to the metric, but no consensus on the correct approach to the substitution process is reached.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the method for summing indices or the substitution process, indicating ongoing confusion and differing interpretations of the calculation steps.

Contextual Notes

Participants express uncertainty regarding the correct application of the summation convention and the specific indices to consider, highlighting potential limitations in their understanding of the metric and its components.

John Greger
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I'm trying to compute the extrinsic curvature. I have the formula and everything I need to plug into the formula. But I get confused when executing this calculation..
I'm trying to compute the extrinsic curvature. I have the formula and everything I need to plug into the formula. But I get confused when executing this calculation..

I have that ##ds^2_{interior} = -u(r)dt^2 + (u(r))^{-1} dr^2 + r^2 d\Omega_3^2##. This is a metric describing the interior and exterior of a bubble. The extrinsic curvacture is given by
\begin{equation}
K_{ab} = N_{\mu; \nu} (\frac{\partial x^\mu}{\partial y^a})(\frac{\partial x^\nu}{\partial y^b}) = ( \frac{\partial N_\mu}{\partial x^\nu } - \Gamma^{k}_{\mu \nu} N_{k}) )(\frac{\partial x^\mu}{\partial y^a})(\frac{\partial x^\nu}{\partial y^b}).
\end{equation}

##N_{\mu; \nu}## is the norm of the bubble which is given by ##N_a = (-\dot{R}, \dot{T},0,0,0)##. Since we are looking for dyamical on the brane, we don't care about the angular part of the metric: ##(t,r, \Omega) \rightarrow (T(\tau), R(\tau), \Omega)##.

##x^\mu## labels bulk metric (I think##(\tau, r, \Omega)##) and ##y^a## labels coordinate on the brane (I think ## (T(\tau), R(\tau), \Omega)##.

The nonzero christoffel sumbols of the Metric are ##\Gamma^r_{rr} = \frac{\partial u / \partial r}{u(r)} = \Gamma^t_{rt}##.

I don't know howto substitute all of this into (1). Should I sum all possible combinations of indices or should I sum the following two combinations ##(\mu, \nu) = (\tau, r) ; (a,b)= (T(\tau), R(\tau))## and ##(\mu, \nu) = (r, \tau) ; (a,b)= (R(\tau), T(\tau))##?

If I get some initial help here it will be straight forward to take it from there I think.

P.S the answer should be $$K_{a,b} = -\frac{1}{u \dot{T}}[\ddot{R} + (1/2) \frac{\partial u}{\partial R}] + u(R) \dot{T} R$$ but I cannot really arrive at this. Any help to get this expression is much apprichiated.
 
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##N_{\mu;\nu}## is the covariant derivative of ##N_\mu##.
 
martinbn said:
##N_{\mu;\nu}## is the covariant derivative of ##N_\mu##.
Hi! Many thanks for your answer. Yes indeed, might have abused language. I believe I expanded it in equation 1 the right way. But I feel that I am confused about how to sum the indices accordingly..
 
You sum the indices with the Einstein summation convention, which basically says you sum over all possible values of repeated indices.

a and b appear on the left hand side, so you are computing 16 quantities, as a and b both vary from 0 to 3 (or possibly 1 to 4, depending on your notation).

For each specific value of a and b, you have one component of ##K_{ab}##. To get the value of that component, you sum over all values of k, ##\mu##, and ##\nu##. Thus if you wrote it out longhand, in general each of the 16 components of ##K_{ab}## would be the sum of 64 terms. Hopefully, though, your metric is simple enough that many of the terms are zero.
 
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