Compute the number of positive integer divisors of 10

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The discussion focuses on calculating the number of positive integer divisors of 10! using its prime factorization. The correct factorization of 10! is identified as 2^8 x 3^4 x 5^2 x 7, leading to the calculation of divisors based on the formula for counting divisors. Initially, a mistake was made in counting the factors of 7, but it was later corrected to include it as two, resulting in the correct total of 270 divisors. The confusion also arose from the mention of 270! being greater than 10!, which was clarified as irrelevant to the divisor count. The final answer for the number of positive integer divisors of 10! is confirmed to be 270.
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Homework Statement
number of positive integer divisors of 10!
Relevant Equations
10!
Compute the number of positive integer divisors of 10!. By the fundamental theorem of arithmetic and the factorial expansion:

10! = 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
= 2 x 5 x 3^2 x 7 x 2 x 3 x 5 x 2^2 x 3 x 2 x 1
= 2^8 x 3^4 x 5^2 x 7

Then there are 9 possibilities for 2, 5 for 3, 3 for 5 and for 7 giving 9 x 5 x 3 = 135.

The book gives 270 as the answer, where am I going wrong?

Thank you!

EDIT:Oops, I should have counted 7 as two giving 9 x 5 x 3 x 2 = 270!
 
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RM86Z said:
Homework Statement:: number of positive integer divisors of 10!
Relevant Equations:: 10!

270!
Isn't that greater than 10! ?
 
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