(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

[tex]\int^{1}_{0}\frac{dx}{\sqrt{1-x^{2}}}[/tex]

2. Relevant equations

None

3. The attempt at a solution

[tex]\int^{1}_{0}\frac{dx}{\sqrt{1-x^{2}}} = sin^{-1}x\right|^{1}_{0}[/tex]

[tex]sin^{-1}x\right|^{1}_{0} = \frac{\pi}{2} - 0[/tex]

so the final answer is just pi/2. I have no problem computing the answer, but it's in the improper integrals section of the textbook....but I don't see this as being an improper integral. There's no need to deal with infinity at all, no asymptotes, no discontinuity on the closed interval [0,1].

Am I missing something?

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# Homework Help: Computing an improper integral

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