Computing Per-Minute Storage for Full HD TV

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The discussion focuses on calculating the per-minute storage requirements for full HD TV at 60 frames per second, with each frame having a resolution of 1920×1080 pixels and 24-bit color. The calculations reveal that one minute of uncompressed video requires approximately 20.86 gigabytes of storage. This large figure highlights the necessity for compression in video formats like DVDs and Blu-Ray, which use significant encoding techniques to reduce file sizes. For instance, a dual-layer Blu-Ray can hold 50GB, enough for only 2.5 minutes of uncompressed video, yet can store over 9 hours of HD video due to compression. The discussion emphasizes the impact of compression on video storage and playback.
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Homework Statement



This question isn't that hard just confusing:

Write a program to compute the per-minute storage requirements for “full
HD” TV at 60 HZ (60 frames per second) where each frame is captured at
a resolution of 1920×1080 pixels using 24-bit color.

Homework Equations



1 pixel = 3 integers
1 integer = 8 bits

The Attempt at a Solution



I said:

Number of pixels one frame = (1920)(1080) = 2073600

Number of integers one frame = (2073600)(3) = 6220800

Number of bits one frame = (6220800)(8) = 49766400

Number of bytes one frame = 49766400/8 = 6220800

Number of kilobytes one frame = (6220800)/1024 = 6075

Number of kilobytes one second = (6075)(60) = 364500

Number of kilobytes one minute = (364500)(60) = 21870000

Number of megabytes one minute = (21870000)/(1024) = 21357.42 approx. = 20.86 gigabytes approx. This looks like a very large number for one minute.
 
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KillerZ said:

Homework Statement



This question isn't that hard just confusing:

Write a program to compute the per-minute storage requirements for “full
HD” TV at 60 HZ (60 frames per second) where each frame is captured at
a resolution of 1920×1080 pixels using 24-bit color.

Homework Equations



1 pixel = 3 integers
1 integer = 8 bits

The Attempt at a Solution



I said:

Number of pixels one frame = (1920)(1080) = 2073600

Number of integers one frame = (2073600)(3) = 6220800

Number of bits one frame = (6220800)(8) = 49766400

Number of bytes one frame = 49766400/8 = 6220800

Number of kilobytes one frame = (6220800)/1024 = 6075

Number of kilobytes one second = (6075)(60) = 364500

Number of kilobytes one minute = (364500)(60) = 21870000

Number of megabytes one minute = (21870000)/(1024) = 21357.42 approx. = 20.86 gigabytes approx. This looks like a very large number for one minute.

I get the same answer. It IS a very large number for one minute. That's why DVDs and cable TV use such heavy compression. e.g., a dual-layer Blu-Ray DVD has 50GB storage capacity TOTAL, enough to hold 2.5 minutes of uncompressed video, not even including audio. The Blu-Ray FAQ claims that you can store over 9 hours of HD video on a 50GB disc, so that shows how extreme the compression is. (Source: http://www.blu-ray.com/faq/ )
 
Ok that makes sense as the question also says "assume no other encoding is done" so it would be uncompressed video.
 
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