Conceptual question - radioactive nucleus stability

AI Thread Summary
A ^{238}_{92} U nucleus can capture a neutron, forming an unstable ^{239}_{92} U nucleus due to an excess of neutrons. To achieve stability without undergoing fission, the nucleus can emit alpha particles, which is classified as alpha decay rather than fission. This process helps balance the neutron-to-proton ratio. The discussion clarifies the distinction between alpha decay and fission. Understanding these decay processes is crucial for grasping nuclear stability.
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Homework Statement



A ^{238}_{92} U nucleus can catch a neutron with small kinetical energy. Then we'll get a ^{239}_{92} U nucleus. This nucleus has too many neutrons compared to the number of protons to be stable. How can the nucleus achieve a better balance between neutrons and protons without fissioning?

Homework Equations


N/A

The Attempt at a Solution



send out \alpha-particle(s)? That's not considered fission, right?
 
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