Hmmm..so what would be the condition required for the pulleys tangential acceleration and the strings and blocks acceleration to be the same?
Let T be the tension in the string, then Td=ζ (Torque); ---(1)where 'd' is the radius of the pulley.
Also, dα=at---(2); where 'α' is the angular acceleration of the pulley imparted by the tension T.
Also, ζ=Iα---(3) ; where 'α' is the angular acceleration of the pulley imparted by the tension T and 'I' is the Moment of Inertia of the pulley about its own axis of rotation. So, If the pulley is considered a cylinder (since we don't consider it of negligible thickness otherwise it would have been a disc). Let the mass of the pulley be mpulley. Also this is a solid cylinder.
Therefore I= (1/2)mpulleyd2---(4)
So, Td=(1/2)mpulleyd2(at/d)---(5)
=>at=2T/mpulley---(6)
So if masses of blocks are m1 and m2; m2>m1, then their acceleration if the pulley is massless is:
ablocks=((m2-m1)/(m2+m1))g---(7); where g is acceleration due to gravity.
at=ablocks, RHS of (6) and (7) should be equal,
2T/mpulley=((m2-m1)/(m2+m1))g---(8)
Also, T=((2m1m2)/(m1+m2))g;---(9)
So,
((4m1m2)/(m1+m2)mpulley)g=((m2-m1)/(m2+m1))g
=>((4m1m2)/(m2-m1))=mpulley
Is that the condition required? For the acceleration of the blocks to remain the same even though the pulley has mass? If this condition is not met, then the acceleration of the blocks would be the same as the acceleration of the pulley provided that the blocks don't skid. Is that correct? Phew!