Conductive Heat Loss: Lower by 4.55% at 70F to 68F

AI Thread Summary
Reducing the indoor temperature from 70°F to 68°F results in a 4.55% decrease in conductive heat loss when the outside temperature is 26°F. The calculation is based on the temperature difference between the inside and outside. The heat conduction through a wall is directly proportional to this temperature difference. The method used to arrive at the percentage involved comparing the differences in temperature. This approach confirms that the reduction in temperature effectively lowers heat loss.
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Homework Statement



If only conductive heat loss was significant for a house, then by what percentage would you lower the heat loss if the temperature was reduced inside from 70°F to 68°F, when the outside temperature is 26°F? (Hint: Try using a ratio.)

Homework Equations



N/A, use a ratio

The Attempt at a Solution



This question was given with no explanation and no examples are present anywhere. I don't know what kind of equation to use since no area or R values are given. I did 70-26 and 68-26 then found the percentage between them which came out to 4.55%. Is this correct?
 
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TPU said:
I did 70-26 and 68-26 then found the percentage between them which came out to 4.55%. Is this correct?
Yes.
The conduction of heat through a wall is proportional to the temperature difference across it (70-26 versus 68-26).
 
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