I Conflict of domain and endpoints in Noether's theorem

AI Thread Summary
The discussion centers on the complexities of endpoint definitions in Noether's theorem and energy conservation derivations. A transformation from q(t) to q'(t) raises questions about the integration of the Lagrangian due to fuzzy endpoint definitions. The correctness of boundary conditions, as stated by Schwichtenberg and Kleinert, is debated, particularly regarding whether variations at the endpoints can be zero. Kleinert's differentiation between variations in Hamilton's principle and Noether's theorem is also questioned, especially the implications of boundary conditions. The conversation emphasizes the necessity of expressing variables in "old coordinates" to clarify these issues and maintain appropriate boundary conditions.
Van Ladmon
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Conflicts arise on boundary when proving energy conservation using Noether's theorem. Different statement appear in Physics from Symmetry and Kleinert's Particles and Quantum Fields.
In the derivation of energy conservation, there is the transformation ##q(t)\rightarrow q'(t)=q(t+\epsilon)##, whose end points are kind of fuzzy. The original path ##q(t)## is only defined from ##t_1## to ##t_2##. If this transformation rule is imposed, ##q'(t_2-\epsilon)=q(t_2)## to ##q'(t_2)=q(t_2+\epsilon)## is not defined in the original path. Then how could the Lagrangian be integrated?

On P.98 of Jakob Schwichtenberg's book Physics from Symmetry, he stated that ##\delta q(t_1)=\delta q(t_2)=0## whereas Kleinert stated in his Particles and Quantum Fields ##\delta q_s(t_a)## and ##\delta q_s(t_b)## are not necessarily ##0##. Who's correct?

This question is different from the endpoint questions since it is already clear that ##q(t_2+\epsilon)\neq q(t_2)##.
 
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You have to express everything in terms of the "old coordinates" including time. Then there's no problem with imposing the appropriate boundary conditions ##\delta q(t_1)=\delta q(t_2)=0## for Hamilton's principle. For time translations the symmetry condition is ##\partial_t L=0##, i.e., ##L=L(q,\dot{q})## and the conserved quantity is ##H=p \cdot q-L## with ##p=\partial L/\partial \dot{q}##.
 
vanhees71 said:
You have to express everything in terms of the "old coordinates" including time. Then there's no problem with imposing the appropriate boundary conditions ##\delta q(t_1)=\delta q(t_2)=0## for Hamilton's principle. For time translations the symmetry condition is ##\partial_t L=0##, i.e., ##L=L(q,\dot{q})## and the conserved quantity is ##H=p \cdot q-L## with ##p=\partial L/\partial \dot{q}##.
But why Kleinert differentiates the two kinds of variations: ##\delta q## used in Hamilton's principle and ##\delta_s q## in Noether's theorem? He says that ##\delta_s q## need not be ##0## on the boundaries. Also, what do you mean by expressing everything in terms of "old coordinates"? Could you please give an example? Thanks.
 
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