Confused about using the integral and infinitesimal?

Click For Summary
The discussion revolves around deriving the volume of a sphere using infinitesimals rather than standard integral formulas. It emphasizes understanding the area of a cross-section of the sphere, which is a disk with an area of πr², and then stacking these disks with infinitesimal thickness to approximate the volume. The concept of infinitesimal thickness allows for the inner and outer surfaces of spherical shells to be treated as having the same area, simplifying calculations. The conversation also suggests that recognizing the volume of a sphere as twice that of a half-sphere can simplify the derivation process. Overall, the discussion seeks clarity on using infinitesimals in volume calculations without relying on traditional integral methods.
Dufoe
Messages
4
Reaction score
0
I don't understand what is meant by "derive the formula for finding the volume of a sphere that uses infinitesimals but not the standard formula for the integral"?
Is this talking about Gauss or what? I'm completely self taught in calculus and I did three proofs already... the old cylinder / cone proof, and the other two used the standard formula for the integral.. Even any link to something that explains this would help. I'm only aware of 7 proofs and I don't get how any of them meet both criteria..? Thanks!
 
Physics news on Phys.org
Possibly the exact wording of the question would help.
 
Yup, as Hector is alluding to, you need to find the thickness of spherical shells. If you find the area of a shell and then multiply by a infinitessimal thickness you get the volume of the infinitessimally thick shell. Integrate these shell volumes to find the volume of the sphere. The idea to realize is that since the thickness of the shell is infinitessimal the shell area is the same in the inner and outer surface of the shell. as the thickness of the shell decreases the inner surface and outer surface areas get closer together. So for an infinitessimal thickness they are the same area.
 
I would start by observing that the volume of a sphere is twice the volume of half a sphere. This makes the formula for one "slice" much simpler.
 
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

Similar threads

  • · Replies 24 ·
Replies
24
Views
6K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
6
Views
3K
Replies
11
Views
7K