- #1
tahayassen
- 270
- 1
I understand that the indefinite integral is like infinite definite integrals, but how come when we calculate the definite integral we simply substitute the two values into the indefinite integral and subtract? Why do we subtract? Why not add?
Also, there aren't the same thing, right? What's the difference between the two?
[tex]\int _{ 0 }^{ t }{ 6t } \neq \int { 6t }[/tex]
Also, there aren't the same thing, right? What's the difference between the two?
[tex]\int _{ 0 }^{ t }{ 6t } \neq \int { 6t }[/tex]