Conservation (energy and momentum) problem

AI Thread Summary
The discussion revolves around an experiment involving a balloon filled with sand that swings and strikes a tissue box, with the aim of determining the coefficient of friction between the box and the table. The user has outlined the forces acting on the box and is attempting to apply Newton's second law to derive equations for acceleration and friction. They are also exploring the principles of conservation of energy and momentum to analyze the collision between the balloon and the box, specifically calculating the velocity of the balloon before impact. Questions arise regarding the proper application of these principles and how to incorporate the spring scale readings into the calculations. Clarification on these concepts is sought to ensure accurate results in both parts of the experiment.
N_L_
Messages
33
Reaction score
0
I'm having trouble with the following experiment. A balloon filled with sand attached to a string swings and hits a tissue box, which then slides to a stop. A spring scale is used to pull the box across the table and the amount of force required is given. The goal is to find the coefficient of friction between the box and the table two ways and then to compare.

http://paer.rutgers.edu/pt3/experiment.php?topicid=4&exptid=141

Part I

The mass of the balloon and tissue box are given. From a short movie you are given the amount of force required by the spring scale.

Box - 161.1 g
Spring scale reading - .25 N

Drawing an FBD gave Fn up, Fg down, Fapp to the right and FF to the left.

Sum Fext=ma
Fg + Fn + Fapp + FF=ma

x) -FF + Fapp = ma
y) Fn-Fg=0

The mass is given as 161.1g = .1611 kg

we read from the spring scale that the Fapp= .25 Newtons

-m*g*mu + .25 = .1611-a
(.1611)(9.8)(mu) + .25 = -.1611a
1.579 mu = .1611a + .25
mu = .1020a + .1583

Is this right so far? Should I just set the equations equal to zero instead...how do you find acceleration then?


Part II

Slide distance after being struck by the balloon - 27.9 cm
Balloon - 54.7 g
Estimated height of the balloon's center of mass - 6.75 cm
Height from which the pendulum balloon is released - 76.1 cm

The directions say to use conservation of energy and momentum to solve.

Momentum:

[mass of box * velocity of box before] + [mass of balloon pendulum * velocity of balloon pendulum before] = [mass of box * velocity of box after] + [mass of balloon pendulum * velocity of balloon pendulum after]

Zero + 54.7vtwo = 161.1voneprime + 54.7vtwoprime

Energy: Before the pendulum is released all of its energy is potential. The box doesn't have kinetic energy or potential energy. If I focus on just the balloon pendulum I can find its velocity just before impact with the box (vtwo) in the above equation. Vtwo = 1.22 m/s

From there, I'm not sure what to do or where exactly to apply conservation of energy (from what starting point to what ending point...). I'm also not sure how to use Q in my energy equation.

Any ideas?
 
Physics news on Phys.org
For part one, I would think that you could assume constant velcocity. (But don't take my word on that).

For part two, I think you would use conservation of energy to find the velocity of the balloon just before it hit the tissue box (potental to kinetic) rather than trying to measure it.

~H
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top