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Conservation of Angular Momentum Using the Hamiltonian

  1. Oct 15, 2009 #1
    1. The problem statement, all variables and given/known data
    The Hamiltonian for a particle mass m, moving in a central force field is given as: H = 1/(2m) * |p^2| - V(r). Take the Hamiltonian to be invariant, such that it can be shown that L = r x p the angular momentum vector is a conserved quantity: dL/dt = {L,H} = 0.


    2. Relevant equations
    q_i-dot = dH/dp_i and p_i-dot = - dH/dq_i


    3. The attempt at a solution
    I do not understand how to go about solving the following problem ( I think I understand what the Hamiltonian is, but I do not understand how to from it to what needs to be proven) To solve the problem I believe I need to get from Hamiltonian's equations to Lagrange's p_i = dL/dx_i-dot and then from there use p-dot * dr + p * dr-dot = 0 where dr is defined as the distance between two vectors r and r+dr.
     
  2. jcsd
  3. Oct 15, 2009 #2

    gabbagabbahey

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    Hi physics2018, welcome to PF!:smile:

    Well, since you are asked to show that [itex]\frac{d\textbf{L}}{dt}=\{\textbf{L},H\}=0[/itex], why not start by computing [itex]\{\textbf{L},H\}[/itex]?
     
    Last edited: Oct 15, 2009
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