Conservation of Energy and the Race between Different Shapes on an Inclined Ramp

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The discussion focuses on calculating the linear speeds of a ring, disk, and sphere released from an inclined ramp using the conservation of energy principle. The objects have identical masses and radii, and the ramp is inclined at 17 degrees over a length of 3.80 meters. The energy equations involve potential energy and rotational kinetic energy, with specific moments of inertia for each shape. The user struggles with the calculations but finds clarity after recognizing the importance of correctly applying the equations, particularly the relationship between linear and angular speeds. The conversation highlights the significance of understanding energy conservation in rotational dynamics.
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Homework Statement


Three uniform objects: a ring, a disk, and a sphere all have identical masses and radii. They are released simultaneously from the top of a ramp 3.80 meters in LENGTH. If the ramp is inclined at θ= 17.0°, use conservation of energy to calculate the linear speed of the ring, disk and sphere.


Homework Equations


Ei=Ef
Iring = mr2
Idisk = (mr2)/2
Isphere = (2mr2)/5


The Attempt at a Solution


Ui + Ki = Uf + Kf
mgh = (1/2)Iω2f + (1/)mv2f <--initial K and final U are zero

then substituting I for Iring
mgh = (1/2)((mr2)(vf)/(r)) + (mv2f)
masses cancel, pulled out 1/2
gh = (1/2)(rvf + v2f)

But that's as far as I can get before I can't understand it.
 
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robertmatthew said:

The Attempt at a Solution


Ui + Ki = Uf + Kf
mgh = (1/2)Iω2f + (1/)mv2f <--initial K and final U are zero

then substituting I for Iring
mgh = (1/2)((mr2)(vf)/(r)) + (mv2f)

Note that ωf is squared.
 
I always end up asking questions on here because of stupid mistakes like that, haha. That made much more sense, with the radii canceling out. Thanks so much.
 
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