Conservation of Energy max height

AI Thread Summary
To find the maximum height and kinetic energy of an arrow fired at a 45-degree angle with an initial velocity of 15 m/s, one must analyze the motion using the equations for kinetic energy (Ek = 1/2mv^2) and potential energy (Ep = mgh). The arrow's initial kinetic energy can be calculated using its mass and initial velocity. At maximum height, the vertical component of the velocity becomes zero, while the horizontal component remains unchanged, allowing for the calculation of potential energy at that height. Understanding the conservation of energy principles is crucial, as the initial kinetic energy converts to potential energy at the peak of the trajectory. The discussion emphasizes the importance of breaking down the velocity into its components to solve the problem accurately.
soul5
Messages
63
Reaction score
0

Homework Statement


An arrow(mass=0.2kg) is fired at a 45 degree angle with an inital velocity of 15 m/s. Find it's max height and kinetic energy when it is at it's max height.


Homework Equations


Ek=1/2mv^2
Ep=mgh


The Attempt at a Solution


I tried breaking it down to x and y components, but I don't know if that's right.
 
Physics news on Phys.org
What is the kinetic and potential energy of the arrow as it is first fired? What is the velocity of the arrow at the maximum height?
 
Max height has to do with potential energy. Kinetic energy at max height is a conceptual question and idea.
 
Tedjn said:
What is the kinetic and potential energy of the arrow as it is first fired? What is the velocity of the arrow at the maximum height?

that's all the info they gave me.
 
No, what I mean is that you can figure out those two things I asked you from the information you are given. Think about what forces act on the arrow. Does the horizontal velocity ever change?
 
Break the velocity into components.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Energy analysis of this system (curved ramp up and a spring)
Replies
29
Views
1K
Conservation of Work/Momentum of Puck Sliding Off Plate
Replies
4
Views
2K
How do I find final velocity using conservation of energy
Replies
4
Views
8K
Conservation of momentum/energy of stacked balls
Replies
6
Views
4K
Conservation of Momentum Problem - Mechanical and Kinetic Energies
Replies
2
Views
901
Firework problem, conservation of energy?
Replies
18
Views
2K
Challenging problem about an impact with a smooth frictionless surface
2
Replies
55
Views
5K
Conservation of energy problem: Ball rolling down inclined plane and then through a loop-the-loop
Replies
10
Views
2K
Conservation of Energy with heat
Replies
5
Views
2K
Accounting for Air Resistance in Conservation of Energy Lab with Bouncing Ball
Replies
13
Views
3K

Hot Threads

Recent Insights

Back
Top