Conservation of Linear Momentum Problem (Need help)

AI Thread Summary
The discussion focuses on solving a conservation of linear momentum problem involving a 4.60-kg ball colliding with a stationary 9.80-kg ball on a frictionless table. Participants clarify that for parts (a) and (b), the collision is elastic, meaning both momentum and kinetic energy are conserved. The concept of the coefficient of restitution being equal to one is emphasized, indicating that the velocity of separation equals the velocity of approach. For part (c), the final velocities can be determined since the balls will stick together in a completely inelastic collision. The conversation highlights the importance of understanding conservation laws in different types of collisions.
Kaleem
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Homework Statement


A 4.60-kg ball, moving to the right at a velocity of +2.31 m/s on a frictionless table, collides head-on with a stationary 9.80-kg ball. Find the final velocities of (a) the 4.60-kg ball and of (b) the 9.80-kg ball if the collision is elastic. (c) Find the magnitude and direction of the final velocity of the two balls if the collision is completely inelastic.

Homework Equations


P = (mvf1+mvf2) - (mvi1+mvi2)

The Attempt at a Solution


I understand part c since they will have a combined mass and the same final velocity and that Vi2=0 however i can't figure out how to solve parts A and B.
 
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hi, welcome to physicsforums :)
For part a) and b) you are meant to assume the collision is elastic. So what kind of condition is this? and can you use this to find an answer to the problem?
 
BruceW said:
hi, welcome to physicsforums :)
For part a) and b) you are meant to assume the collision is elastic. So what kind of condition is this? and can you use this to find an answer to the problem?
Since the collision is elastic would it be safe to assume that kinetic energy is conserved?
 
yes! and what else is conserved in the collision?
 
BruceW said:
yes! and what else is conserved in the collision?
I'm not exactly sure, is it mechanical energy?
 
there are not potential energies here. Think of something else that is conserved in collision. (hint: it is conserved in inelastic collisions too).
 
As there is a elastic collision so you can use that (##e##(coefficient of restitution)=1). So velocity of separation is equal to the velocity of approach in common normal direction. This will give you a relation between the velocities of the balls. You have mentioned a name of a concept in the title of this thread. Just use that concept. :smile:
 
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