Conservation of linear momentum when friction is present

AI Thread Summary
In discussions about the conservation of linear momentum during inelastic collisions with friction, it's noted that while external frictional forces act on the system, the momentum can still be considered conserved during the collision due to the non-impulsive nature of friction. Participants argue that the system can be defined as Earth + A + B, allowing for momentum conservation despite friction's presence. Although momentum is technically not conserved when considering all forces, the effect of friction is negligible during the brief collision time. The analogy of pouring water into the ocean is used to illustrate that while momentum is altered, the change is immeasurable compared to the total momentum of the Earth. Ultimately, for practical purposes, momentum conservation holds true in these scenarios.
zorro
Messages
1,378
Reaction score
0
See the figure-

attachment.php?attachmentid=32890&stc=1&d=1299618716.jpg


The block A collides inelastically with the block B. I have seen in 2 of my books that they apply conservation of momentum in such problems along x-direction. According to me, since there is an external frictional force acting, the linear momentum is not conserved.

Is it that they consider Earth + A + B to be the system and ignore the velocity of the Earth ?
Please throw some light on this.
 

Attachments

  • Untitled.jpg
    Untitled.jpg
    5.7 KB · Views: 3,233
Physics news on Phys.org
The friction does transfer some of the momentum to the table (or whatever). Simpler experiment - put a book on the table and give it a push (impart momentum) and it will soon stop (momentum transferred to table).
 
Hi Abdul! :smile:
Abdul Quadeer said:
The block A collides inelastically with the block B. I have seen in 2 of my books that they apply conservation of momentum in such problems along x-direction. According to me, since there is an external frictional force acting, the linear momentum is not conserved.

As you know, momentum is not conserved after the collision, and we have to use the work energy theorem instead.

But during the collision, the friction force is non-impulsive, ie it acts for such a short time that its effect can be ignored …

it has no effect on the sudden change in momentum …

so momentum is conserved. :smile:
 
tiny-tim said:
But during the collision, the friction force is non-impulsive, ie it acts for such a short time that its effect can be ignored …

So ideally the momentum is not conserved?
 
Abdul Quadeer said:
So ideally the momentum is not conserved?

Yes, but well below the threshold of accuracy with which you could measure the velocities. :wink:
 
Is this approximation same as the situation when we ignore the momentum of the Earth by considering A+B+Earth as our system?
 
I don't think so (I don't really see the analogy :redface:).
 
But that would violate mathematical laws. You must get the same equation by two different methods. Otherwise either one of them is wrong.
 
Momentum is conserved. You change the momentum of the Earth itself. But that amount is so small compared to Earth's total momentum that you could never measure it. So for all practical purposes the momentum is treated as "lost". Think of it this way. If you pour a glass of water into the ocean you increase its volume. But if you go to any station that measures sea level you will never ever observe a change in sea level because of your action. It is the same with the momentum of a sliding object on the Earth. The momentum is still there, you just can't measure it.
 
Back
Top