Conservation of mass - equation understanding

Click For Summary

Discussion Overview

The discussion revolves around understanding the conservation of mass equation represented as $$ \dot{m}_{in} - \dot{m}_{out} = \frac{dm_{CV}}{dt} $$, focusing on the interpretation of the right-hand side (RHS) and the notation used in the equation. The scope includes conceptual clarification and technical explanation related to mass flow rates and control volumes.

Discussion Character

  • Conceptual clarification
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant seeks clarification on the meaning of $$ \frac{dm_{CV}}{dt} $$ and questions why it is not expressed as $$ \dot{dm_{CV}} $$.
  • Another participant compares the RHS to a bank account analogy, suggesting it represents the rate of change of mass within the control volume.
  • There is a suggestion that the left-hand side could also be expressed as $$ \frac{{dm_{in}}}{dt} - \frac{{dm_{out}}}{dt} $$, indicating a misunderstanding of notation.
  • A participant clarifies that the over-dot notation does not imply a time derivative and explains the definition of $$ \dot{m}_{in} $$ in terms of density, velocity, and cross-sectional area.
  • There are inquiries about the meaning of "CV," which is confirmed to stand for "control volume."

Areas of Agreement / Disagreement

Participants express differing views on the notation and interpretation of the equation, with no consensus reached on the best way to express the RHS or the implications of the notation used.

Contextual Notes

Participants have not fully defined their variables, which may lead to further confusion regarding the terms used in the equation.

Ketler
Messages
3
Reaction score
0
Homework Statement
Understanding conservation of mass equation
Relevant Equations
$$ \dot{m}_{in} - \dot{m}_{out} = \frac{dm_{CV}}{dt}$$
Hello All,

I have a problem to understand this equation:

$$ \dot{m}_{in} - \dot{m}_{out} = \frac{dm_{CV}}{dt} $$

It supposed to describe change in the mass of the control volume during a process.

Two terms on the left are the total mass flow rates in and out of the system. I struggle to understand RHS.

What $$ \frac{dm_{CV}}{dt} $$ means and why it is not equal to $$\dot{dm_{CV}}$$?

Many thanks for all your help.

Lukas
 
Physics news on Phys.org
The rhs is the rate of change of mass within the control volume. It's like a bank account. (Rate of money in) minus (rate of money out) equal (rate of accumulation of money within the account).
 
Thanks for your answer. So if it is a rate of change, why is it not written as:
$$ \dot{dm_{CV}} $$

My assumption is, LHS can be also written as:
$$ \frac{{dm_{in}}}{dt} - \frac{{dm_{out}}}{dt} = ... $$
 
Ketler said:
Homework Statement: Understanding conservation of mass equation
Relevant Equations: $$ \dot{m}_{in} - \dot{m}_{out} = \frac{dm_{CV}}{dt}$$

Hello All,

I have a problem to understand this equation:

$$ \dot{m}_{in} - \dot{m}_{out} = \frac{dm_{CV}}{dt} $$

It supposed to describe change in the mass of the control volume during a process.

Two terms on the left are the total mass flow rates in and out of the system. I struggle to understand RHS.

What $$ \frac{dm_{CV}}{dt} $$ means and why it is not equal to $$\dot{dm_{CV}}$$?

Many thanks for all your help.

Lukas
Can you define your variables, please?
 
Ketler said:
Thanks for your answer. So if it is a rate of change, why is it not written as:
$$ \dot{dm_{CV}} $$

My assumption is, LHS can be also written as:
$$ \frac{{dm_{in}}}{dt} - \frac{{dm_{out}}}{dt} = ... $$
No. It's a notational thing. The over-dot does not mean a time derivative. ##\dot{m}_{in}## the rate of flow in: $$\dot{m}_{in}=\rho_{in}v_{in}A_{in}$$where ##\rho_{in}## is the density of the inlet stream, ##v_{in}## is the velocity of the inlet stream (at the inlet to the control volume), and ##A_{in}## is the cross sectional area of the inlet flow conduit.
 
  • Like
Likes   Reactions: Ketler
Chestermiller said:
No. It's a notational thing. The over-dot does not mean a time derivative. ##\dot{m}_{in}## the rate of flow in: $$\dot{m}_{in}=\rho_{in}v_{in}A_{in}$$where ##\rho_{in}## is the density of the inlet stream, ##v_{in}## is the velocity of the inlet stream (at the inlet to the control volume), and ##A_{in}## is the cross sectional area of the inlet flow conduit.
what does CV mean here?
 
pines-demon said:
what does CV mean here?
Control volume
 

Similar threads

  • · Replies 33 ·
2
Replies
33
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
12
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
7
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K