Conservation of momentum and velocity question

AI Thread Summary
The discussion revolves around a physics problem involving a 1000N stone box supported by two steel cylinders, with a constant force of 100N applied. The user attempts to determine the velocity of the box when one cylinder reaches the corner, initially calculating acceleration using F=ma. There is uncertainty about the correct formulas to apply, particularly regarding momentum and energy transfer. The conversation highlights the need to relate linear velocity and angular velocity in the context of the problem. Ultimately, the focus is on finding the appropriate equations to solve for the box's velocity.
affordable
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Homework Statement




The 1000N stone box is supported by
two steel cylinders A and B at 100N each. The system is at rest
in the position shown when the constant
force P = 100N is applied.

Determine the velocity of the stone box C when cylinder A
has reached the left corner of the box.

http://img801.imageshack.us/i/unledom.jpg/

Homework Equations





The Attempt at a Solution



Ugh. It logged me out, so my explanation will be pretty weak.

What I did was use the circumference of a circle as 20/(30pi) as the distance needed to get the cylinder to the end. I used F=ma to find the acceleration of the box in the x direction is 1/10 in/sec^2.

From here, I'm unsure. I assume that this is a momentum problem that transfers energy to the cylinders, but I'm not for sure which formula to use.

I'm thinking about using total work-.5mv^2+.5*I*(omega)^2.

Would the acceleration in the x direction be equal for the cylinders and the box?
 
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hi affordable! :smile:

(have an omega: ω and try using the X2 icon just above the Reply box :wink:)
affordable said:
Would the acceleration in the x direction be equal for the cylinders and the box?

nooo :redface:

what are the speeds of the top middle and bottom of the cylinder? :wink:
I'm thinking about using total work-.5mv^2+.5*I*(omega)^2.

that's the one!

now plug in a formula relating v and ω, and solve :smile:
 
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