Conservation of momentum - bullet/pendulum

AI Thread Summary
The discussion revolves around a physics problem involving the conservation of momentum between a bullet and a pendulum block. The bullet, weighing 0.02 kg, is fired at a 30-degree angle, while the pendulum block weighs 2 kg and reaches a maximum height of 0.2 meters. The calculations suggest an initial velocity of approximately 199.98 m/s for the bullet, but the unclear parameters of the pendulum's length and pivot point raise questions about the feasibility of the collision. Participants express confusion over the trajectory of the bullet and whether the collision is elastic or inelastic. Overall, the problem lacks sufficient details for a definitive solution, leading to uncertainty in the calculations.
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Homework Statement


Bullet = 0.02 kg
pendulum block = 2 kg

bullet fired from (0m,0m) with velocity of (x m/s, 30 deg)
pendulum block located (30m, 30deg)
the maximum height reached by pendulum is 0.2 meter

what is the value of X


Homework Equations


I've tried several ways to approach this problem. the problem is the angle that it hits the bullet.


The Attempt at a Solution



If the angle was out of the problem, i get an answer of 199.98 m/s/s. i used mgh=1/2mv^2 to get the velocity final, then worked backwards to plug that into the conservation of momentum equation:

(0.02)(Vi) = (2.02)(1.98) = 199.98

this is about as far as i got without running into a wall. What i think is that the 199.98 is the X component, and using that I can solve for the resultant. But how?
 
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Hi z2420, Welcome to Physics Forums.

It's not clear how this pendulum is supposed to look. How long is the pendulum string? Where does it pivot? Where is its "maximum height" measured from?

If the pendulum block is represented as a point mass at location 30m @30°, and the bullet is fired from the origin at 30°, how can the bullet ever strike the block if gravity is acting? (Trajectory will be parabolic, always below a slope 30° line from the origin). Is the bullet striking the block an elastic or inelastic collision?

If the pendulum string is just 0.1 meters long, any sufficiently speedy bullet will always make it reach its apex of 0.2m above its lowest point; The pendulum will go around in circles about its pivot! :smile:

Did the original problem statement come with a diagram?
 
there was no diagram and the problem stated was very unclear in itself

this is what i thought

the bullet in traveling upward at an angle of 30 degrees. Hitting the block and going inside. The block and bullet swing upwards at 0.2m. The length of the pendulum string is not stated. the pendulum looks like a string hanging 90 degrees from the top.

i think the 199.98 is the x trajectory. So under this (maybe incorrect) assumption, i calculated the y trajectory to get the resultant = 230.91 = initial velocity of bullet

think that's right?
 
I think that there are too many inconsistencies and unknown properties in the problem to make a valid judgment. Sorry.:redface:
 
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