1. The problem statement, all variables and given/known data A gun is fired vertically into a 1.40kg block of wood at rest directly above it. If the bullet has a mass of 21.0g and a speed of 310m/s, how high will the block rise into the air after the bullet becomes imbedded into it? 2. Relevant equations m1v1+m2v2= m1v11+ m2v12 3. The attempt at a solution So I first converted 21.0 grams into .021kg because I know you use kg for this equation. After substituing in a few things this is as far as I have gotten: m1v1+m2v2= m1v11+ m2v12 (.021)(0)+(1.40)(0)=(.021)(310)+(1.40)(V) V= -4.65m/s as the final velocity of the block so from here I have a few questions first did I do this part correctly and from here how would I proceed in order to determine how high the block will go?