Conservation of momentum question

AI Thread Summary
The discussion centers on a conservation of momentum problem involving a ball colliding with a stationary wall. The initial analysis suggests that the wall's velocity is zero, leading to confusion about the correct application of momentum equations. It is clarified that conservation of momentum applies to closed systems without external forces, but the wall and Earth exert forces during the collision. The change in momentum of the ball is emphasized, noting that while the magnitude remains the same, the direction changes, necessitating vector addition. Ultimately, the participant confirms their understanding after recalculating and agreeing with the correct approach.
David112234
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Homework Statement


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Homework Equations


m1v1+m2v2=m1v1+m1v1 after

The Attempt at a Solution


my answer = -1m1v1
because the wall is not moving so its velocity is 0
therefore
m1v1 = m1-v1 after
I put -v because it is the same just bounces in the opposite X direction
I found somewhere online the answer should be 2 * mv * sin(θ)
I don't understand why
 
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David112234 said:
because the wall is not moving so its velocity is 0
therefore
m1v1 = m1-v1 after
Conservation of momentum only applies to a closed system, i.e. no outside forces. The wall exerts a force. If you include the wall, the Earth exerts a force on the wall. If you include the Earth then in fact it will acquire a velocity from the impact, but so small you could not possibly measure it.
Just consider the change in momentum of the ball (as a vector).
 
haruspex said:
Conservation of momentum only applies to a closed system, i.e. no outside forces. The wall exerts a force. If you include the wall, the Earth exerts a force on the wall. If you include the Earth then in fact it will acquire a velocity from the impact, but so small you could not possibly measure it.
Just consider the change in momentum of the ball (as a vector).
It is the same as before only its x component changes, first it goes right, then it goes left
 
David112234 said:
It is the same as before only its x component changes, first it goes right, then it goes left
The magnitude is the same as before, but momentum and velocity are vectors. What is the net change in velocity?
 
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haruspex said:
The magnitude is the same as before, but momentum and velocity are vectors. What is the net change in velocity?
Oh so I do vector addition
I did the math out and got the same answer, thank you
 
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