Is the expression still valid for large differences in radius?

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SUMMARY

The expression for energy conservation in a ball rolling on a semicircular track is valid when the radius of the track (R) is not significantly larger than the radius of the ball (r). The equation mg(R-r) = (1/2)I0ω² + (1/2)Iω1² + (1/2)mv² holds true, where I0 is the moment of inertia of the ball about the center of the track. However, when R is much larger than r, the translational kinetic energy of the ball overlaps with the rotational energy about the center of the track, making the I0 term redundant. Thus, the equation simplifies by removing the I0 term to avoid double counting.

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AdityaDev
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If a ball rolls in a semicircular track starting from one end of track,( the track is kept vertical) and if radius of ball is r and radius of track is R
is this expression correct? (When ball reaches lowest point)
##mg(R-r)=\frac{1}{2}I_0\omega^2 + \frac{1} {2}I\omega_1^2+\frac{1}{2}mv^2##
where ##I_0## is the moment of inertia about centre of track since the ball moves in a circle and moment of inertia is mr^2
The second is for rotation of ball
the third is translational kinetic energy

what changes should I make if R is very very larger than r?
 
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You are double counting the motion of the ball. The translational kinetic energy of the ball is the same thing as the rotational energy about the center of the track, so the I0 term is redundant.
 
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Your first and third term (on the right hand side) represent the same energy. Once is enough.

(Khashishi beat me to it!)
 
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