Constructing a Function F: Natural Restriction Homework

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Homework Statement



Let (xn) n ∈ N, be a succession. Construct a function F: [0,plus infinity[ to Rn (if possible
continuous) whose restriction to the naturals is (xn) n ∈ N, ie xn = F (n) for all n ∈ N, and such that ∃ limx → + ∞ F (x) = L if and only if ∃ Limn → + ∞ xn = L

The Attempt at a Solution



What does restriction to the naturals mean? Does it mean that F(n) must be a natural? If so I can't find out what function has domain [0,plus infinity[ and produces naturals.

Thanks
 
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benf.stokes said:

Homework Statement



Let (xn) n ∈ N, be a succession. Construct a function F: [0,plus infinity[ to Rn (if possible
continuous) whose restriction to the naturals is (xn) n ∈ N, ie xn = F (n) for all n ∈ N, and such that ∃ limx → + ∞ F (x) = L if and only if ∃ Limn → + ∞ xn = L

The Attempt at a Solution



What does restriction to the naturals mean? Does it mean that F(n) must a natural? If so I can't find out what function has domain [0,plus infinity[ and produces naturals.

Thanks
No, it is the domain, not the range, that is restricted. You are looking for a function, F(x), (where x can be any non-negative real number) such that for x= n, a non-negative integer, F(x)= F(n)= x_n.

For example, if x_n= 2/n, then you would take F(x)= 2/x.
 
Thanks for the reply. Would F(x) = sqrt(x)/(x^2+1) be an acceptable function then?
 
Looks to me like it will work. What is \lim_{x\to\infty}\sqrt{x}/(x^2+ 1)?
What is \lim_{n\to\infty}\sqrt(n)/(n^2+ 1)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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