Constructing a Perfect Set in R Without Rational Numbers

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Homework Statement


Is there any nonempty perfect set in R which contains no rational number?


Homework Equations


A set E is perfect iff E is closed and every point of E is a limit point of E


The Attempt at a Solution


We should avoid rational numbers to become limit points, so we have to kick out countable segments with rational numbers...But how can I construct the set so that the remaining irrational numbers are still limit points and no isolated point exists?
 
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micromass said:
The construction of such a set is quite tricky. You will have to modify the construction of the Cantor set in such a way that it misses the rationals. See http://en.wikipedia.org/wiki/Smith–Volterra–Cantor_set for general information about such a set.

How to modify it? Rational numbers are dense in R...
 
Throw out a rational number at each step of the construction.
 
micromass said:
Throw out a rational number at each step of the construction.
yes, you are right...sorry, I made a mistake in my proof... but now I can understand it...thank U very much...
 
micromass said:
Throw out a rational number at each step of the construction.
We should choose the end points of each segments carefully to make sure that the end points are all irrational numbers and the set is still closed!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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