# Continuity of the first Maxwell equation.

1. Nov 3, 2007

### Bert

Suppose that we will proof the continuity of the first maxwell equation:

So we have $$div(\vec{E})=\frac{1}{\epsilon _0} \rho$$ than $$\iiint \ div(\vec{E}) = \oint_v \vec{E} d\vec{s}=\iiint \frac{1}{\epsilon _0 } \rho$$
than follewed $$E_{y1} l -E_{y2}l=Q$$

Therefore E must continue is this a good proof? Thanks.

2. Nov 3, 2007

### ZapperZ

Staff Emeritus
You have not defined what "y" direction is. So your y components are ambiguous.

Only the parallel component of the E-field (parallel to the surface) is continuous.

Zz.

3. Nov 3, 2007

### Bert

Thanks if I define my y component as the parallel one. Is than the proof oké?