1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Continuity of the first Maxwell equation.

  1. Nov 3, 2007 #1
    Suppose that we will proof the continuity of the first maxwell equation:

    So we have [tex]div(\vec{E})=\frac{1}{\epsilon _0} \rho [/tex] than [tex]\iiint \ div(\vec{E}) = \oint_v \vec{E} d\vec{s}=\iiint \frac{1}{\epsilon _0 } \rho [/tex]
    than follewed [tex]E_{y1} l -E_{y2}l=Q [/tex]

    Therefore E must continue is this a good proof? Thanks.
  2. jcsd
  3. Nov 3, 2007 #2


    User Avatar
    Staff Emeritus
    Science Advisor
    Education Advisor

    You have not defined what "y" direction is. So your y components are ambiguous.

    Only the parallel component of the E-field (parallel to the surface) is continuous.

  4. Nov 3, 2007 #3
    Thanks if I define my y component as the parallel one. Is than the proof oké?
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Threads - Continuity Maxwell equation Date
B I have a problem with Maxwell's demon Mar 7, 2018
I Principle of virtual work for continuous systems Jan 18, 2018
A Fluids: Continuity and Conservation of Mass Jan 12, 2018
A Linearized Continuity (Fluids) May 11, 2017