Contracting Loop in a Magnetic Field

AI Thread Summary
An elastic circular loop is placed in a 0.81 T magnetic field, with its diameter changing from 19 cm to 6.8 cm in 0.45 seconds. The initial approach to calculate the average induced emf was incorrect due to using the change in diameter instead of the change in area. After recalculating the magnetic flux for both the initial and final states, the correct change in flux was determined. The discussions highlighted the importance of interpreting the term "magnitude" in the context of induced emf. Ultimately, the correct answers for both the induced emf and current were achieved with collaborative assistance.
Angie K.
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Homework Statement



An elastic circular loop in the plane of the paper lies in a 0.81 T magnetic field pointing into the paper. If the loop's diameter changes from 19 cm to 6.8 cm in 0.45 s,

a. what is the magnitude of the average induced emf?

b. If the loop's resistance is 2.3 Ω, what is the average induced current I during the 0.45 s?

Homework Equations



emf = change in flux * B / change in time

magnetic flux = B*A cos Theta

The Attempt at a Solution



Using the equation from above,

the distance that I am going to use is .19m - .068m = .122 m (change in distance)

magnetic flux = (0.81T)(pi)(0.122m)^2 cos 0

= 3.7875*10^-2 T/m^2

emf = (3.7875*10^-2 T/m^2) / 0.45s = 8.4167*10^-2 Volts

Which is wrong but I am not sure where I went wrong.
Maybe something with the distance? Because I feel like that's the one place where I could have messed up...

Thanks in advance!
 
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You made a mistake here:
Angie K. said:
the distance that I am going to use is .19m - .068m = .122 m (change in distance)

magnetic flux = (0.81T)(pi)(0.122m)^2 cos 0

You need to calculate the change in area, not the change in diameter.
You want this: ## \Delta A = A_{final}-A_{initial} = \pi r_{final}^2-\pi r]_{initial}^2 ##
Try that and see if it works.
 
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Angie K. said:
the distance that I am going to use is .19m - .068m = .122 m (change in distance)

magnetic flux = (0.81T)(pi)(0.122m)^2 cos 0

This is where the mistake is. Try finding the initial total flux and then the final total flux (after 0.45 s). Use these to get the change in flux.

[You can ignore my post. BiGyElLoWhAt already posted]
 
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Beat you ;)
 
BiGyElLoWhAt said:
Beat you ;)
:H
 
BiGyElLoWhAt said:
You made a mistake here:You need to calculate the change in area, not the change in diameter.
You want this: ## \Delta A = A_{final}-A_{initial} = \pi r_{final}^2-\pi r]_{initial}^2 ##
Try that and see if it works.

BiGyElLoWhAt said:
Beat you ;)

For initial flux : .81T (pi*r (.19^2) = 9.18633e-2
For final flux: .81T (pi*r (.068^2) = 1.17666e-2

so the change in flux is 1.17666e-2 - 9.18633e-2 = - .0800967

so I plug that into find Emf:

magnitude of emf (- .0800967/0.45s) and it still isn't the right answer.
 
Angie K. said:
For initial flux : .81T (pi*r (.19^2) = 9.18633e-2
For final flux: .81T (pi*r (.068^2) = 1.17666e-2

so the change in flux is 1.17666e-2 - 9.18633e-2 = - .0800967

so I plug that into find Emf:

magnitude of emf (- .0800967/0.45s) and it still isn't the right answer.
Looks good except you need to interpret the word "magnitude".
 
TSny said:
Looks good except you need to interpret the word "magnitude".

BiGyElLoWhAt said:
Beat you ;)

I got the right answer for both parts. Thanks to you both for the help!
 
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