Control system with equation C = A*x + B*dx/dt

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Homework Help Overview

The problem involves a control system described by the equation C = A*x + B*dx/dt, relating to classical mechanics and robotics. The original poster seeks to understand how the steady state and half-life of the system change when the mass of the robot is doubled.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to analyze the steady state and half-life, questioning the impact of mass on these parameters. Some participants suggest manipulating the equation to explore solutions, while others express uncertainty about the meanings of steady state and half-life.

Discussion Status

Participants are actively engaging with the problem, offering algebraic manipulations and expressing curiosity about the underlying concepts. There is a recognition of the need for further understanding of exponential decay and its relation to the problem.

Contextual Notes

The original poster indicates a lack of familiarity with physics concepts, which may affect their interpretation of the problem. There is also a mention of homework constraints, as the question arose in an exam context.

zsero
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Homework Statement


This question came up in a computer science / robotics exam and I still don't know the solution for it. I figured out that it's classical mechanics related, so I thought this might be the best place to ask it.

Suppose a control system is described by the equation C = A*x + B*dx/dt, where B is proportional to the mass of the robot. The behaviour of the system can be characterised by the steady state (e.g. the asymptotic velocity of the robot) and the half-life time of the decrease of the distance to the steady state. Explain how the steady state and the half-life change if the mass of the robot is doubled.

Homework Equations


C = A*x + B*dx/dt

The Attempt at a Solution


I've figured out that the steady state doesn't change, as it happens when dx/dt is 0, thus B is not affecting the solution.

And this is how far I understand it. Can you explain to me, what kind of movement is this, what is the real-life meaning of the steady state and half-life for this movement and that how to calculate the change in the half-life?
 
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hi zsero! :smile:

write it Bdx/dt = C - Ax, then solve it by "separating the variables" :wink:
 
tiny-tim said:
hi zsero! :smile:

write it Bdx/dt = C - Ax, then solve it by "separating the variables" :wink:

OK, I arrive at the following equation:

-B/A*ln(x) = c*t + k1

My problem here is that I don't understand the meaning of the equations and that what is asked by half-life and steady state.

How can I get the half-time from this equation?
 
zsero said:
-B/A*ln(x) = c*t + k1

ok, now multiply by -1/B and then e-to-the on both sides …

x = xoe-ACt/B (where xo = e-kA/B)

does that look familiar? :wink:
 
Thanks for the help! Actually, I'm not a Physics student, so I don't really know, but I'd guess it's the exponential delay. So if B doubles then the constant becomes half, thus the half-life becomes double. Is this correct?
 
good guess! :smile:

but you really should make yourself familiar with half-life (and exponential decay generally) …

look it up in wikipedia or the pf library :wink:
 
Thanks for the help!
 

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