Convergence: Epsilon-N Definition

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Homework Help Overview

The discussion revolves around the epsilon-N definition of convergence, specifically regarding a sequence and its behavior as n approaches infinity. Participants are exploring whether the sequence converges and how to apply the convergence definition without a specified limit L.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express uncertainty about determining convergence and discuss the relevance of constants in the sequence. Questions arise about logarithmic properties and their application in the context of convergence. There is also a mention of using L'Hospital's Rule to analyze the limit of the sequence.

Discussion Status

Some participants have provided guidance on logarithmic rules and suggested reviewing them for clarity. There is an ongoing exploration of how to express the sequence in a simplified form and its implications for the epsilon-N argument. Multiple interpretations of the sequence's behavior are being considered.

Contextual Notes

Participants are navigating the complexities of applying the epsilon-N definition without a clear limit, raising questions about assumptions and the setup of the problem.

UOAMCBURGER
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Homework Statement


45068354_253709458645469_3577857059221143552_n.png?_nc_cat=106&_nc_ht=scontent.fhlz2-1.png


Homework Equations


epsilon - N definition of convergence [/B]

The Attempt at a Solution


Not sure how to determine whether this sequence converges or not. Thought it could have something to do with the fact that e^2 and e^3 are just constants, so when n > infinity those e terms become negligible in comparison. If you had to apply convergence definition how could you do that without L? [/B]
 

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UOAMCBURGER said:

Homework Statement


View attachment 232999

Homework Equations


epsilon - N definition of convergence

The Attempt at a Solution


Not sure how to determine whether this sequence converges or not. Thought it could have something to do with the fact that e^2 and e^3 are just constants, so when n > infinity those e terms become negligible in comparison. If you had to apply convergence definition how could you do that without L?
Do you know rules for logarithms ?

Such as ##\ \ln(a\cdot b) =\ln(a)+\ln(b)\,?##

What is ## \ \ln(e^2) \, ?##
 
SammyS said:
Do you know rules for logarithms ?

Such as ##\ \ln(a\cdot b) =\ln(a)+\ln(b)\,?##

What is ## \ \ln(e^2) \, ?##
oh yes i do. Update: I used L'Hospital's Rule to find that the sequence converges to 2. But now separating the logarithms you get 2+ln(n^2)/3+ln(n), so would that change my answer I get using L'Hospital's rule? or can i assume an converges to 2 and then use the definition with L = 2?
 
UOAMCBURGER said:
oh yes i do. Update: I used L'Hospital's Rule to find that the sequence converges to 2. But now separating the logarithms you get 2+ln(n^2)/3+ln(n), so would that change my answer I get using L'Hospital's rule? or can i assume an converges to 2 and then use the definition with L = 2?
Did you mean ##\ \displaystyle \frac{2+\ln(n^2)}{3+\ln(n) } \,?##

If you write a "fraction" all on one line, you need to enclose the numerator and denominator each in parentheses; as in (2+ln(n^2))/(3+ln(n)) .

Also, you may further find that it helps to review rules for logarithms in general.

Another helpful one here is ##\ \displaystyle \ln(a^M) = M\ln(a)\ .##

In addition to this:
You know that the limit is 2, so take the difference between 2 and ##\ \displaystyle \frac{2+\ln(n^2)}{3+\ln(n) } \,.\ ## That should be useful for an ## \epsilon - N\ ## argument. It will also give you what you need to write ##\ \displaystyle \frac{2+\ln(n^2)}{3+\ln(n) } \ ## in a simplified form.
 

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