Convergence in probability distribution

1. Dec 29, 2013

Elekko

1. The problem statement, all variables and given/known data
Let $$X_n \in Ge(\lambda/(n+\lambda))$$ $$\lambda>0.$$ (geometric distribution)
Show that $$\frac{X_n}{n}$$ converges in distribution to $$Exp(\frac{1}{\lambda})$$

2. Relevant equations
I was wondering if some kind of law is required to use here, but I don't know what
Does anyone know how this actually can be shown?
I'm taking a probability class, but the course literature I'm using is does not actually cover examples in this part at all. So it makes me hard to understand this :(

Last edited: Dec 29, 2013
2. Dec 29, 2013

Ray Vickson

What is "Ge(.)"?

3. Dec 29, 2013

Elekko

Geometric distribution

4. Dec 29, 2013

Ray Vickson

(1) What is the definition of convergence in distribution? (If you do not know or understand this you cannot profitably proceed further.)

(2) Assuming you have answered (1) correctly, just write down the actual quantities involved (distributions, etc.) and look at what happens when n → ∞. (You should find this to be straightforward; if not, you need to go back to some earlier courses to fill in some missing background.)