Convergence of $\displaystyle\sum\frac{n^5}{2^n}$

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Discussion Overview

The discussion centers around the convergence of the series $\displaystyle\sum\frac{n^5}{2^n}$. Participants explore various convergence tests, including the ratio test and the root test, to analyze the behavior of the series.

Discussion Character

  • Technical explanation, Mathematical reasoning, Homework-related

Main Points Raised

  • One participant inquires about the convergence of the series $\displaystyle\sum\frac{n^5}{2^n}$.
  • Another participant suggests using the ratio test and the root test, indicating that these tests should provide the necessary information regarding convergence.
  • A later reply presents a calculation using the ratio test, concluding that the limit $\displaystyle\lim_{n\to\infty}\left|\frac{a_{n+1}}{a_n}\right|=\frac{1}{2}$, which implies convergence.
  • Another participant states that for the general form $a_n=\dfrac{n^k}{2^n}$, the root test indicates that the series converges for all values of $k$.

Areas of Agreement / Disagreement

There is no explicit consensus on the convergence of the series, as some participants provide calculations and interpretations that suggest convergence, while others have not yet responded to the proposed methods.

Contextual Notes

The discussion does not clarify the assumptions behind the tests used or the specific conditions under which the convergence is claimed.

Who May Find This Useful

Students and individuals interested in series convergence, particularly those studying mathematical analysis or related fields.

alexmahone
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Does the following series converge?

$\displaystyle\sum\frac{n^5}{2^n}$
 
Last edited:
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Well what tests did you try?the ratio test and the root test both give you what you need. Try them. If you need more hints let us know.Mohammad
 
fawaz said:
Well what tests did you try?the ratio test and the root test both give you what you need. Try them. If you need more hints let us know.Mohammad

$\displaystyle\lim_{n\to\infty}\left|\frac{a_{n+1}}{a_n}\right|=\lim_{n\to\infty}\frac{(n+1)^5}{2n^5}=\frac{1}{2}$

So, $\displaystyle\sum\frac{n^5}{2^n}$ converges.
 
Last edited:
$a_n=\dfrac{n^k}{2^n},$ so by the root test the series always converges for all $k.$
 

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