Convergence of $\displaystyle\sum\frac{n^5}{2^n}$

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SUMMARY

The series $\displaystyle\sum\frac{n^5}{2^n}$ converges definitively. Both the ratio test and the root test confirm this conclusion, with the ratio test yielding a limit of $\displaystyle\frac{1}{2}$ as $n$ approaches infinity. The general term is defined as $a_n=\dfrac{n^k}{2^n}$, and the root test indicates that the series converges for all values of $k$. Thus, the convergence of this series is established through rigorous testing methods.

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alexmahone
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Does the following series converge?

$\displaystyle\sum\frac{n^5}{2^n}$
 
Last edited:
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Well what tests did you try?the ratio test and the root test both give you what you need. Try them. If you need more hints let us know.Mohammad
 
fawaz said:
Well what tests did you try?the ratio test and the root test both give you what you need. Try them. If you need more hints let us know.Mohammad

$\displaystyle\lim_{n\to\infty}\left|\frac{a_{n+1}}{a_n}\right|=\lim_{n\to\infty}\frac{(n+1)^5}{2n^5}=\frac{1}{2}$

So, $\displaystyle\sum\frac{n^5}{2^n}$ converges.
 
Last edited:
$a_n=\dfrac{n^k}{2^n},$ so by the root test the series always converges for all $k.$
 

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