I Convergence of ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}##

Wuberdall
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Hi Physics Forums,

I have a problem that I am unable to resolve.

The sequence ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}## of positive integer powers of ##\mathrm{sinc}(x)## converges pointwise to the indicator function ##\mathbf{1}_{\{0\}}(x)##. This is trivial to prove, but I am struggling to decide if the convergence is uniform or not.

I hope that someone in here can help me, either by providing a reference or a sketch proof.

Thanks in regards.
 
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Wuberdall said:
Hi Physics Forums,

I have a problem that I am unable to resolve.

The sequence ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}## of positive integer powers of ##\mathrm{sinc}(x)## converges pointwise to the indicator function ##\mathbf{1}_{\{0\}}(x)##. This is trivial to prove, but I am struggling to decide if the convergence is uniform or not.

I hope that someone in here can help me, either by providing a reference or a sketch proof.

Thanks in regards.
What does the uniform convergence theorem say about continuous functions?
 
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haruspex said:
What does the uniform convergence theorem say about continuous functions?
Thanks,

Each of the ##\mathrm{sinc}^n(x)## functions in the sequence are continuous. Thus IF the sequence where to converge uniformly to ##\mathbf{1}_{\{0\}}##, then ##\mathbf{1}_{\{0\}}## has to be continuous (which it is not). Consequently, the sequence ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}## is not uniformly converging.
 
Wuberdall said:
Thanks,

Each of the ##\mathrm{sinc}^n(x)## functions in the sequence are continuous. Thus IF the sequence where to converge uniformly to ##\mathbf{1}_{\{0\}}##, then ##\mathbf{1}_{\{0\}}## has to be continuous (which it is not). Consequently, the sequence ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}## is not uniformly converging.
Quite so.
 
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