Conversion of Electrical Energy to Heat

AI Thread Summary
The experiment demonstrated the conversion of electrical energy to heat using an Ohmic heating coil, yielding a power output of 30 watts. However, the heating power calculated for the water was only 20 watts, raising questions about the efficiency of the conversion process. The discrepancy may be attributed to inefficiencies in the experiment, such as heat loss to the environment or the container. Additionally, not all electrical power may be converted to heat, with some energy remaining in the heating element. Overall, the findings highlight the complexities involved in energy conversion and the factors affecting efficiency.
ALLIRIX
Messages
4
Reaction score
0
I've done a school experiment converting electrical energy to heat. P=VI was used to find the electric power going through the Ohmic heating coil, and got an answer of 30 watts. It was used to heat 0.2kg of water and the equation Q/t = m×c×T/t was used to find the Heating Power which gave an answer of 20 watts. I was wondering if the lower answer is only due to inefficiencies of the experiment or that not 100% of the power is converted and some remains in the heating element as electrical energy.
 
Physics news on Phys.org
Could be inconsistencies, power given off in other forms of energy, heat transferred into the air, or heat transferred into the container holding the water.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Heating efficiency of a Heat Pump and a Space Heater
Replies
1
Views
2K
Energy Conservation between mechanical and electrical
Replies
7
Views
1K
First Law of Thermo: Audience body heat warming a concert hall
Replies
25
Views
1K
Thermodynamics: Internal Energy, Heat and Work Problem
Replies
1
Views
2K
How Does Newton's Law of Cooling Affect Heat Loss Calculations?
Replies
2
Views
2K
Calculate the Heat Loss in a Hot Water Tank from a Shower
Replies
2
Views
3K
Calculating Energy Stored and Dissipated in a Capacitor Discharge
Replies
1
Views
1K
Incandescent Bulb - suitable approximation for voltage-current curve
Replies
2
Views
900
Physics Homework about using Electricity to Heat Flowing Water
Replies
9
Views
1K
Examples of conversion of gravitational PE to heat energy?
Replies
2
Views
7K

Hot Threads

Recent Insights

Back
Top