- #1

- 1

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r= (15)/(3-2cos(theta))

I'm lost!!

Please Help!!

I'm lost!!

Please Help!!

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- Thread starter Burger2010
- Start date

- #1

- 1

- 0

r= (15)/(3-2cos(theta))

I'm lost!!

Please Help!!

I'm lost!!

Please Help!!

- #2

- 34

- 0

- #3

- 96

- 0

Given:

[tex] r = \frac{15}{3-2cos(\theta)} [/tex]

[tex] r = \sqrt{x^2+y^2} [/tex]

[tex] x = rcos(\theta) [/tex]

[tex] y = rsin(\theta) [/tex]

substituting

[tex]\sqrt{x^2+y^2} = \frac{15}{3-2(\frac{x}{\sqrt{x^2+y^2}})} [/tex]

- #4

arildno

Science Advisor

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[tex]y=\pm\frac{\sqrt{5(15-x)(x+3)}}{3}[/tex]

Thus, the solution is a closed curve.

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